> Read Brian Gerst's response. My whole point was that interrupts are
> not associated with a user process, which I have shown. If the designer
> decided to use a portion of some kernel element as an interrupt stack
If? Since interrupts may happen when you are within ring 0 you
have no choice other than allow them to use the current kernel stack.
And code the kernel stuff allowing that possibilty.
> it does not change this essential fact. The user processes` stack is
> not even used for the return address of the interrupt so the user's
> stack-pointer is never touched at all.
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