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On 1 Sep 1998, Andreas Schwab wrote:
> Clifford Wolf <clifford@clifford.at> writes:
>
> |> I've just had a look at the GNU make info page (File: make.info, Node:
> |> Execution) and they say at this page that make executes all commands
> |> useing a subshell and that it uses /bin/sh as subshell if the $(SHELL)
> |> variable is not set.
> |>
> |> So it invokes a subshell anyway (regardless if $(SHELL) is set or not).
>
> No, it doesn't. If SHELL is unset or set to /bin/sh then make will parse
> the command by itself, unless it is complex (containing shell
> metacharacters) or uses shell builtin commands or if $IFS is non-standard.
> See job.c:construct_command_argv_internal. From the user's point of view
> this does not make any difference (except performance-wise), that's why
> it's not documented except in the sources.
I attached a patch which fixes the broken Makefiles. I don't know if we
use bash features - makeing the suggestion that /bin/sh is bash -
somewhere else in the kernel too.
- clifford
-- -- -- -- -- -- -- -- -- -- -- -- --
Clifford Wolf
magnet - Internet at Work IRC: efnet / clifford
Director of System Development http://www.clifford.at/
e-mail: c.wolf@magnet.at email: god@clifford.at
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