Re: [PATCH] IB/hfi1: Fix potential deadlock on &sde->flushlist_lock

From: Leon Romanovsky
Date: Wed Jul 05 2023 - 01:52:49 EST


On Wed, Jul 05, 2023 at 01:42:31AM +0800, Chengfeng Ye wrote:
> > Plus, we already in context where interrupts are stopped.
>
> Indeed they can be called from .ndo_start_xmit callback and
> the document said it is with bh disabled.
>
> But I found some call chain from the user process that seems could
> be called from irq disabled context. For sdma_send_txlist(),
> there is a call chain.
>
> -> hfi1_write_iter() (.write_iter callback)
> -> hfi1_user_sdma_process_request()
> -> user_sdma_send_pkts()
> -> sdma_send_txlist()
>
> The .write_iter seems not to disable irq by default, as mentioned by
> https://www.kernel.org/doc/Documentation/filesystems/vfs.txt
> And I didn't find any explicit disabling or bh or irq along the call path,
> and also see several copy_from_usr() which cannot be invoked under
> irq context.
>
>
> For sdma_send_txreq(), there is a call chain.
>
> -> qp_priv_alloc()
> -> iowait_init() (register _hfi1_do_tid_send() as a work queue)
> -> _hfi1_do_tid_send() (workqueue)
> -> hfi1_do_tid_send()
> -> hfi1_verbs_send()
> -> sr(qp, ps, 0) (sr could points to hfi1_verbs_send_dm())
> -> hfi1_verbs_send_dma()
> -> sdma_send_txreq()
>
> _hfi1_do_tid_send() is a work queue without irq disabled by default,
> I also check the remaining call path and also found that there is no explicit
> irq disable, instead the call site of hfi1_verbs_send() is exactly after
> spin_lock_irq_restore(), seems like a hint that it is probably called withirq
> enable.

Right, that path is called in process context and can sleep, there is no
need in irq disabled variant there.

>
> Another hint is that the lock acquisition of
> spin_lock_irqsave(&sde->tail_lock, flags);
> just before my patch in the same function also disable irq, seems like another
> hint that this function could be called with interrupt disable,

Exactly, we already called to spin_lock_irqsave(), there is no value in
doing it twice.
void f() {
spin_lock_irqsave(...)
spin_lock_irqsave(...)
....
spin_unlock_irqrestore(...)
spin_unlock_irqrestore(...)
}

is exactly the same as
void f() {
spin_lock_irqsave(...)
spin_lock(...)
....
spin_unlock(...)
spin_unlock_irqrestore(...)
}

Thanks