Re: [PATCH] bitmap: bitmap_parse takes a kernel buffer instead of a user buffer

From: inaky
Date: Wed Oct 04 2006 - 11:52:37 EST


> Joe wrote:
>> I guess I am a sucker for no-transient-buffer (bufferless?)
>
> Ah - that explains Joe's preference for putting the actual implementing
> code in the user version - it gets to pull in the user string one
> char at a time, avoiding a malloc'd buffer.

I tend to gree w/ Joe there.

I wonder if a hybrid would be ok, although I the pseudo impl
I propose below is kind of dirty, but some people might find it
justified enough:

static
__bitmap_parse(const void *_buf, size_t size, enum { KERNEL, USER } type,
unsigned long *dst, int nbits)
{
const char __user *ubuf = _buf;
const char *buf = _buf;
...
switch(type) {
case USER:
if (get_user(c, ubuf++))
return -EFAULT;
break;
case KERNEL:
c = *buf++;
break;
default:
BUG();
...
}


int bitmap_parse(const char *buf, unsigned int buflen,
unsigned long *maskp, int nmaskbits) {
return __bitmap_parse(buf, buflen, KERNEL, maskp, nmaskbits);
}


int bitmap_parse_user(const char __user *buf, unsigned int buflen,
unsigned long *maskp, int nmaskbits) {
return __bitmap_parse(buf, buflen, USER, maskp, nmaskbits);
}


[that or exposing __bitmap_user() as a extern / EXPORT and putting
bitmap_parse{,_user}() as an inline in the header file]

It's nitty-gritty, but it removes the kmalloc from the equation...

--
Inaky
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