> > which breaks __builtin_return_address(0).
>
> Here __builtin_return_address(0) doesn't use the frame-pointer (%ebp) at
> all. It gets the address of the caller from %esp that obviously has to
> remain valid since first or before you have to run `ret`. So as you are
> able to run `ret` you are able to grab the return address of the function
> at any time even without a frame pointer.
oops, then it was higher-order (eg. __builtin_return_address(1)) that
works only with a valid %ebp frame pointer. anyway, a show() function
probably shows us more about the call path of the process.
-- mingo
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