Re: [PATCH v1] rust: add improved version of `ForeignOwnable::borrow_mut`

From: Andreas Hindborg (Samsung)
Date: Wed Aug 23 2023 - 06:10:14 EST



Alice Ryhl <aliceryhl@xxxxxxxxxx> writes:

> Andreas Hindborg <nmi@xxxxxxxxxxxx> writes:
>>> + /// Borrows a foreign-owned object mutably.
>>> + ///
>>> + /// This method provides a way to access a foreign-owned value from Rust mutably. It provides
>>> + /// you with exactly the same abilities as an `&mut Self` when the value is Rust-owned, except
>>> + /// that this method does not let you swap the foreign-owned object for another. (That is, it
>>> + /// does not let you change the address of the void pointer that the foreign code is storing.)
>>
>> How about this:
>>
>> "For a smart pointer P<T> this method provides mutable access to T if
>> &mut P<T> would allow mutable access to T. Otherwise it provides
>> immutable access to T."
>>
>> The point is that the method provides access to the pointee, not the
>> smart pointer itself. In fact it is perfectly fine to do a mem::swawp()
>> for the pointee in the case of Box and depending on interpretation the
>> sentence "does not let you swap the foreign-owned object for another" is
>> confusing.
>
> Yeah, I agree that the phrasing is somewhat confusing.
>
> How about this:
>
> /// This method provides a way to access a foreign-owned value from Rust mutably. It provides
> /// you with exactly the same abilities as an `&mut Self` when the value is Rust-owned, except
> /// that the address of the object must not be changed.
> ///
> /// Note that for types like [`Arc`], an `&mut Arc<T>` only gives you immutable access to the
> /// inner value, so this method also only provides immutable access in that case.
> ///
> /// In the case of `Box<T>`, this method gives you the ability to modify the inner `T`, but it
> /// does not let you change the box itself. That is, you cannot change which allocation the box
> /// points at.

Sounds good 👍

BR Andreas