Re: [PATCH] PCI: rcar-ep: Include linux/pci-epf.h instead of linux/pci-epc.h

From: Alistair Francis
Date: Wed Jul 05 2023 - 21:44:44 EST


On Wed, Jul 5, 2023 at 11:15 PM Krzysztof Wilczyński <kw@xxxxxxxxx> wrote:
>
> Hello,
>
> > > > > pci-epc.h doesn't define the members of the pci_epf_header struct, so
> > > > > trying to access them results in errors like this:
> > > > >
> > > > > error: invalid use of undefined type 'struct pci_epf_header'
> > > > > 167 | val = hdr->vendorid;
> > > > >
> > > > > Instead let's include pci-epf.h which not only defines the
> > > > > pci_epf_header but also includes pci-epc.h.
> > >
> > > [...]
> > > > It is odd that the the build bot did not detect this...
> > >
> > > This is a bit of a surprise to me too, especially since none of the usual
> > > bots pick this up, and I can't seem to find such a failure in the nightly
> > > CI logs either.
> > >
> > > Alistair, how did you stumble into this issue? Also, which version or
> > > a tree would that be?
> >
> > I was building the kernel with this defconfig [1] inside OpenEmbedded.
> > It was the 6.4-rc7 kernel, specifically this one [2].
> >
> > 1: https://github.com/damien-lemoal/buildroot/blob/rockpro64_ep_v23/board/pine64/rockpro64_ep/linux.config
> > 2: https://github.com/damien-lemoal/linux/tree/rockpro64_ep_v23
>
> Thank you! Much appreciated.
>
> So, the vanilla kernel does not have headers arranged like this custom tree
> that Damien maintains for his own needs, per:
>
> - https://elixir.bootlin.com/linux/v6.4-rc7/source/include/linux/pci-epc.h
> - https://elixir.bootlin.com/linux/v6.4-rc7/source/include/linux/pci-epf.h
>
> I suppose, there are some changes that break it for you, for example:
>
> https://github.com/damien-lemoal/linux/commit/c7aa8ddd76a141b975a097532050a76c6a58c436
>
> So, I cannot take this patch as it would break vanilla kernel for us. :)

Urgh! Sorry about that. I should have double checked if it was an
issue upstream. Thanks for looking into it though

Alistair

>
> Try building using vanilla kernel, and see if that helps.
>
> Krzysztof