Re: [RFC] fprobe call of rethook_try_get faults

[Steven Rostedt]

On Wed, 7 Jun 2023 09:42:30 -0700
Jiri Olsa <olsajiri@xxxxxxxxx> wrote:

> I can't really reliable reproduce this, but while checking the code, I wonder
> we should call rethook_free only after we call unregister_ftrace_function like
> in the patch below

Yeah, I think you're right!

> 
> jirka
> 
> 
> ---
> diff --git a/kernel/trace/fprobe.c b/kernel/trace/fprobe.c
> index 18d36842faf5..0121e8c0d54e 100644
> --- a/kernel/trace/fprobe.c
> +++ b/kernel/trace/fprobe.c
> @@ -364,19 +364,13 @@ int unregister_fprobe(struct fprobe *fp)
>  		    fp->ops.saved_func != fprobe_kprobe_handler))
>  		return -EINVAL;
>  
> -	/*
> -	 * rethook_free() starts disabling the rethook, but the rethook handlers
> -	 * may be running on other processors at this point. To make sure that all
> -	 * current running handlers are finished, call unregister_ftrace_function()
> -	 * after this.
> -	 */
> -	if (fp->rethook)
> -		rethook_free(fp->rethook);

The above only waits for RCU to finish and then starts to free rethook.

This also means that something could be on the trampoline already and was
preempted. It could be that this code path gets preempted. Anyway, I don't
see how freeing rethook is safe before disabling all users.

Reviewed-by: Steven Rostedt (Google) <rostedt@xxxxxxxxxxx>

-- Steve


> -
>  	ret = unregister_ftrace_function(&fp->ops);
>  	if (ret < 0)
>  		return ret;
>  
> +	if (fp->rethook)
> +		rethook_free(fp->rethook);
> +
>  	ftrace_free_filter(&fp->ops);
>  
>  	return ret;