[PATCH] ARM: memset: cast the constant byte to unsigned char

From: Kursad Oney
Date: Wed May 17 2023 - 14:14:28 EST


memset() description in ISO/IEC 9899:1999 (and elsewhere) says:

The memset function copies the value of c (converted to an
unsigned char) into each of the first n characters of the
object pointed to by s.

The kernel's arm32 memset does not cast c to unsigned char. This results
in the following code to produce erroneous output:

char a[128];
memset(a, -128, sizeof(a));

This is because gcc will generally emit the following code before
it calls memset() :

mov r0, r7
mvn r1, #127 ; 0x7f
bl 00000000 <memset>

r1 ends up with 0xffffff80 before being used by memset() and the
'a' array will have -128 once in every four bytes while the other
bytes will be set incorrectly to -1 like this (printing the first
8 bytes) :

test_module: -128 -1 -1 -1
test_module: -1 -1 -1 -128

The change here is to 'and' r1 with 255 before it is used.

Fixes: 1da177e4c3f4 ("Linux-2.6.12-rc2")
Signed-off-by: Kursad Oney <kursad.oney@xxxxxxxxxxxx>

---

arch/arm/lib/memset.S | 1 +
1 file changed, 1 insertion(+)

diff --git a/arch/arm/lib/memset.S b/arch/arm/lib/memset.S
index d71ab61430b2..de75ae4d5ab4 100644
--- a/arch/arm/lib/memset.S
+++ b/arch/arm/lib/memset.S
@@ -17,6 +17,7 @@ ENTRY(__memset)
ENTRY(mmioset)
WEAK(memset)
UNWIND( .fnstart )
+ and r1, r1, #255 @ cast to unsigned char
ands r3, r0, #3 @ 1 unaligned?
mov ip, r0 @ preserve r0 as return value
bne 6f @ 1
--
2.37.3

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