fs/namei.c: Make status likely to be ECHILD in lookup_fast()

[Steven Rostedt]

From:  Steven Rostedt (VMware) <rostedt@xxxxxxxxxxx>

Running my yearly branch profiling code, it detected a 100% wrong branch
condition in name.c for lookup_fast(). The code in question has:

		status = d_revalidate(dentry, nd->flags);
		if (likely(status > 0))
			return dentry;
		if (unlazy_child(nd, dentry, seq))
			return ERR_PTR(-ECHILD);
		if (unlikely(status == -ECHILD))
			/* we'd been told to redo it in non-rcu mode */
			status = d_revalidate(dentry, nd->flags);

If the status of the d_revalidate() is greater than zero, then the function
finishes. Otherwise, if it is an "unlazy_child" it returns with -ECHILD.
After the above two checks, the status is compared to -ECHILD, as that is
what is returned if the original d_revalidate() needed to be done in a
non-rcu mode.

Especially this path is called in a condition of:

	if (nd->flags & LOOKUP_RCU) {

And most of the d_revalidate() functions have:

	if (flags & LOOKUP_RCU)
		return -ECHILD;

It appears that that is the only case that this if statement is triggered
on two of my machines, running in production.

Signed-off-by: Steven Rostedt (VMware) <rostedt@xxxxxxxxxxx>
---
diff --git a/fs/namei.c b/fs/namei.c
index d4a6dd772303..8dd734efae9b 100644
--- a/fs/namei.c
+++ b/fs/namei.c
@@ -1495,7 +1495,7 @@ static struct dentry *lookup_fast(struct nameidata *nd,
 			return dentry;
 		if (unlazy_child(nd, dentry, seq))
 			return ERR_PTR(-ECHILD);
-		if (unlikely(status == -ECHILD))
+		if (likely(status == -ECHILD))
 			/* we'd been told to redo it in non-rcu mode */
 			status = d_revalidate(dentry, nd->flags);
 	} else {