Re: [PATCH] btrfs: let btrfs_delete_unused_bgs() to clean relocated bgs

From: Josef Bacik
Date: Tue Sep 06 2016 - 08:54:16 EST


On 09/05/2016 12:32 AM, Naohiro Aota wrote:
2016-09-02 (é) ã 09:35 -0400 ã Josef Bacik ãããæãããã:
On 09/02/2016 03:46 AM, Naohiro Aota wrote:

Currently, btrfs_relocate_chunk() is removing relocated BG by
itself. But
the work can be done by btrfs_delete_unused_bgs() (and it's better
since it
trim the BG). Let's dedupe the code.

While btrfs_delete_unused_bgs() is already hitting the relocated
BG, it
skip the BG since the BG has "ro" flag set (to keep balancing BG
intact).
On the other hand, btrfs cannot drop "ro" flag here to prevent
additional
writes. So this patch make use of "removed" flag.
btrfs_delete_unused_bgs() now detect the flag to distinguish
whether a
read-only BG is relocating or not.


This seems racey to me. We remove the last part of the block group,
it ends up
on the unused_bgs_list, we process this list, see that removed isn't
set and we
skip it, then later we set removed, but it's too late. I think the
right way is
to actually do a transaction, set ->removed, manually add it to the
unused_bgs_list if it's not already, then end the transaction. This
way we are
guaranteed to have the bg on the list when it is ready to be
removed. This is
my analysis after looking at it for 10 seconds after being awake for
like 30
minutes so if I'm missing something let me know. Thanks,

I don't think a race will happen. Since we are holding
delete_unused_bgs_mutex here, btrfs_delte_unused_bgs() checks ->removed
flag after we unlock the mutex i.e. we setup the flag properly. For a
case btrfs_delete_usused_bgs() checks the BG before we hold
delte_unused_bgs_mutex, then that BG is removed by it (if it's empty)
and btrfs_relocate_chunk() should never see it.


Ok that's what I was missing, thanks

Reviewed-by: Josef Bacik <jbacik@xxxxxx>

Josef