Re: [PATCH V5 1/2] cpufreq: Handle sorted frequency tables more efficiently

From: Francesco Lavra
Date: Mon Jun 27 2016 - 06:11:24 EST


Hi,

On 06/27/2016 06:29 AM, Viresh Kumar wrote:
cpufreq drivers aren't required to provide a sorted frequency table
today, and even the ones which provide a sorted table aren't handled
efficiently by cpufreq core.

This patch adds infrastructure to verify if the freq-table provided by
the drivers is sorted or not, and use efficient helpers if they are
sorted.
<snip>
@@ -610,6 +617,227 @@ int cpufreq_boost_trigger_state(int state);
int cpufreq_boost_enabled(void);
int cpufreq_enable_boost_support(void);
bool policy_has_boost_freq(struct cpufreq_policy *policy);
+
+/* Find lowest freq at or above target in a table in ascending order */
+static inline int cpufreq_table_find_index_al(struct cpufreq_policy *policy,
+ unsigned int target_freq)
+{
+ struct cpufreq_frequency_table *table = policy->freq_table;
+ unsigned int freq;
+ int i, best = -1;
+
+ for (i = 0; table[i].frequency != CPUFREQ_TABLE_END; i++) {
+ freq = table[i].frequency;
+
+ if (freq >= target_freq)
+ return i;
+
+ best = i;
+ }
+
+ return best;
+}
+
+/* Find lowest freq at or above target in a table in descending order */
+static inline int cpufreq_table_find_index_dl(struct cpufreq_policy *policy,
+ unsigned int target_freq)
+{
+ struct cpufreq_frequency_table *table = policy->freq_table;
+ unsigned int freq;
+ int i, best = -1;
+
+ for (i = 0; table[i].frequency != CPUFREQ_TABLE_END; i++) {
+ freq = table[i].frequency;
+
+ if (freq == target_freq)
+ return i;
+
+ if (freq > target_freq) {
+ best = i;
+ continue;
+ }
+
+ /* No freq found below target_freq */

"below" should be "above"

+/* Find closest freq to target in a table in ascending order */
+static inline int cpufreq_table_find_index_ac(struct cpufreq_policy *policy,
+ unsigned int target_freq)
+{
+ struct cpufreq_frequency_table *table = policy->freq_table;
+ unsigned int freq;
+ int i, best = -1;
+
+ for (i = 0; table[i].frequency != CPUFREQ_TABLE_END; i++) {
+ freq = table[i].frequency;
+
+ if (freq == target_freq)
+ return i;
+
+ if (freq < target_freq) {
+ best = i;
+ continue;
+ }
+
+ /* No freq found below target_freq */
+ if (best == -1)
+ return i;
+
+ /* Choose the closest freq */
+ if (target_freq - table[best].frequency > freq - target_freq)
+ return i;
+
+ return best;
+ }
+
+ return best;
+}
+
+/* Find closest freq to target in a table in descending order */
+static inline int cpufreq_table_find_index_dc(struct cpufreq_policy *policy,
+ unsigned int target_freq)
+{
+ struct cpufreq_frequency_table *table = policy->freq_table;
+ unsigned int freq;
+ int i, best = -1;
+
+ for (i = 0; table[i].frequency != CPUFREQ_TABLE_END; i++) {
+ freq = table[i].frequency;
+
+ if (freq == target_freq)
+ return i;
+
+ if (freq > target_freq) {
+ best = i;
+ continue;
+ }
+
+ /* No freq found below target_freq */

"below" should be "above"

+ if (best == -1)
+ return i;
+
+ /* Choose the closest freq */
+ if (target_freq - table[best].frequency > freq - target_freq)

Here, table[best].frequency > target_freq, and freq < and target_freq, so you should reverse the sign of both sides of the inequation:

if (table[best].frequency - target_freq > target_freq - freq)

+ return i;
+
+ return best;
+ }
+
+ return best;
+}

Regards,
Francesco