Re: [RESEND][PATCH] Bluetooth: Make request workqueue freezable

From: Marcel Holtmann
Date: Tue May 19 2015 - 11:22:38 EST


Hi Alan,

>>>> I am not convinced. Now we are hacking the Bluetooth core layer
>>>> (which has nothing to do with the drivers suspend/resume or
>>>> probe) to do something different so that we do not see this
>>>> warning.
>>>>
>>>> I can not do anything about the platform in question choosing a
>>>> unplug/replug for suspend/resume instead of having a proper USB
>>>> suspend and resume handling. That is pretty much out of our
>>>> control.
>
> Actually one can do something about this. I mean, one _can_ implement
> proper USB suspend and resume handling in the Bluetooth driver. At
> this point the details aren't clear to me, but perhaps if the driver in
> question had a reset_resume callback then it might work better.

the btusb.ko driver has suspend/resume support. Are you saying we also need reset_resume support?

>>>> I would rather have the USB subsystem delay the probe()
>>>> callback if we tell it to.
>
> This is possible. I am not sure it would be the right thing to do,
> though. What happens if the probe routine gets called early on during
> the boot-up procedure, before userspace is up and running? The same
> thing should happen here.

For modules this will be hard. Since you need userspace before being able to load the modules. If built-in code, then in theory this might be possible. Depending on the order of the init sections.

>>>> Of just have request_firmware()
>>>> actually sleep until userspace is ready. Seriously, why is
>>>> request_firmware not just sleeping for us.
>
> It won't work. The request_firmware call is part of the probe
> sequence, which in turn is part of the resume sequence. Userspace
> doesn't start running again until the resume sequence is finished. If
> request_firmware waited for userspace, it would hang.

Then I really have no idea on how to solve this unless we silence the warning from request_firmware. From a driver perspective we go back trough probe(). So the driver has to treat this as a new device.

Regards

Marcel

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