[PATCH 4/4] rtc: pxa: request rtc irqs when probe/remove the device

From: Chao Xie
Date: Wed Nov 28 2012 - 21:25:44 EST


The original pxa_rtc_open/pxa_rtc_release will be called
when the /dev/rtc0 is opened or closed.
In fact, these two functions will register/unregister the irqs.
User application will use /dev/rtc0 to read the rtc time or set
the alarm. The rtc should still run indepent of open/close the
rtc device.
So only register the irqs when probe the device,
and disable clock and unregister the irqs when remove the device.

Signed-off-by: Chao Xie <chao.xie@xxxxxxxxxxx>
---
drivers/rtc/rtc-pxa.c | 11 +++++++++--
1 files changed, 9 insertions(+), 2 deletions(-)

diff --git a/drivers/rtc/rtc-pxa.c b/drivers/rtc/rtc-pxa.c
index 29646af..19abeb8 100644
--- a/drivers/rtc/rtc-pxa.c
+++ b/drivers/rtc/rtc-pxa.c
@@ -340,8 +340,6 @@ static int pxa_rtc_proc(struct device *dev, struct seq_file *seq)
}

static const struct rtc_class_ops pxa_rtc_ops = {
- .open = pxa_rtc_open,
- .release = pxa_rtc_release,
.read_time = pxa_rtc_read_time,
.set_time = pxa_rtc_set_time,
.read_alarm = pxa_rtc_read_alarm,
@@ -435,6 +433,11 @@ static int __init pxa_rtc_probe(struct platform_device *pdev)
}
}

+ ret = pxa_rtc_open(&pdev->dev);
+ if (ret) {
+ dev_err(&pdev->dev, "Unable to request irqs for rtc\n");
+ goto err_open;
+ }
/*
* If the clock divider is uninitialized then reset it to the
* default value to get the 1Hz clock.
@@ -461,6 +464,8 @@ static int __init pxa_rtc_probe(struct platform_device *pdev)
return 0;

err_rtc_reg:
+ pxa_rtc_release(&pdev->dev);
+err_open:
if (pxa_rtc->id == RTC_PXA95X)
iounmap(pxa_rtc->base_psbr);
err_map_base_psbr:
@@ -477,6 +482,8 @@ static int __exit pxa_rtc_remove(struct platform_device *pdev)

rtc_device_unregister(pxa_rtc->rtc);

+ pxa_rtc_release(&pdev->dev);
+
spin_lock_irq(&pxa_rtc->lock);
iounmap(pxa_rtc->base);
spin_unlock_irq(&pxa_rtc->lock);
--
1.7.4.1

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