Re: [PATCH] block: Make rq_affinity = 1 work as expected.

[Shaohua Li]

2011/8/8 Tao Ma <tm@xxxxxx>:
> On 08/08/2011 12:33 PM, Shaohua Li wrote:
>> 2011/8/8 Tao Ma <tm@xxxxxx>:
>>> Hi Shaohua,
>>> On 08/08/2011 10:58 AM, Shaohua Li wrote:
>>>> 2011/8/5 Jens Axboe <jaxboe@xxxxxxxxxxxx>:
>>>>> On 2011-08-05 06:39, Tao Ma wrote:
>>>>>> From: Tao Ma <boyu.mt@xxxxxxxxxx>
>>>>>>
>>>>>> Commit 5757a6d76c introduced a new rq_affinity = 2 so as to make
>>>>>> the request completed in the __make_request cpu. But it makes the
>>>>>> old rq_affinity = 1 not work any more. The root cause is that
>>>>>> if the 'cpu' and 'req->cpu' is in the same group and cpu != req->cpu,
>>>>>> ccpu will be the same as group_cpu, so the completion will be
>>>>>> excuted in the 'cpu' not 'group_cpu'.
>>>>>>
>>>>>> This patch fix problem by simpling removing group_cpu and the codes
>>>>>> are more explicit now. If ccpu == cpu, we complete in cpu, otherwise
>>>>>> we raise_blk_irq to ccpu.
>>>>>
>>>>> Thanks Tao Ma, much more readable too.
>>>> Hi Jens,
>>>> I rethought the problem when I check interrupt in my system. I thought
>>>> we don't need Tao's patch though it makes the code behavior like before.
>>>> Let's take an example. My test box has cpu 0-7, one socket. Say request
>>>> is added in CPU 1, blk_complete_request occurs at CPU 7. Without Tao's
>>>> patch, softirq will be done at CPU 7. With it, an IPI will be directed to CPU 0,
>>>> and softirq will be done at CPU 0. In this case, doing softirq at CPU 0 and
>>>> CPU 7 have no difference and we can avoid an ipi if doing it in CPU 7.
>>> I totally agree with your analysis, but what I am worried is that this
>>> does change the old system behavior.
>>> And without this patch actually '1' and '2' in rq_affinity has the same
>>> effect now in your case. If you do prefer the new codes and the new
>>> behavior, then '1' don't need to exist any more(since from your
>>> description it seems to only adds an additional IPI overhead and no
>>> benefit), or '2' is totally unneeded here.
>> with rq_affinity 2, CPU 1 will do the softirq in above case. it's
>> still different
>> like the rq_affinity 1 case.
> OK, so let's see what's going on without the patch in case rq_affinity = 1.
> If the complete cpu and the request cpu are in the same group, the
> complete cpu will call softirq.
> If the complete cpu and the request cpu are not in the same group, the
> group cpu of the request cpu will call softirq.
>
> These behaviors are totally different. How can you tell the user what's
> going on there? And that' the reason we want 0, 1, 2 for rq_affinity. If
> the user does care about the extra IPI(in your case), fine, just set
> rq_affinty = 2.
rq_affinity=2: finish request in each cpu
rq_affinity=1: finish request in one CPU for each socket.
Even without your patch, rq_affinity=1 finish request in one CPU too.
Remember the controller only has one interrupt source. the only difference
is request isn't always finished in the first CPU of a socket. I didn't
think this is a behavior change which user even cares about.
I originally worried about blk_complete_request can be called for all
CPUs, but this isn't true.

Thanks,
Shaohua
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