Re: [ltt-dev] [RFC git tree] Userspace RCU (urcu) for Linux(repost)

[Paul E. McKenney]

On Mon, Feb 09, 2009 at 02:05:09PM -0500, Mathieu Desnoyers wrote:
> * Paul E. McKenney (paulmck@xxxxxxxxxxxxxxxxxx) wrote:
> > On Mon, Feb 09, 2009 at 10:37:42AM -0800, Paul E. McKenney wrote:
> > > On Mon, Feb 09, 2009 at 01:13:41PM -0500, Mathieu Desnoyers wrote:
> > > > * Paul E. McKenney (paulmck@xxxxxxxxxxxxxxxxxx) wrote:
> > 
> > [ . . . ]
> > 
> > > > You know what ? Changing RCU_GP_CTR_BIT to 16 uses a
> > > > testw %ax, %ax instead of a testb %al, %al. The trick here is that
> > > > RCU_GP_CTR_BIT must be a multiple of 8 so we can use a full 8-bits,
> > > > 16-bits or 32-bits bitmask for the lower order bits.
> > > > 
> > > > On 64-bits, using a RCU_GP_CTR_BIT of 32 is also ok. It uses a testl.
> > > > 
> > > > To provide 32-bits compability and allow the deepest nesting possible, I
> > > > think it makes sense to use
> > > > 
> > > > /* Use the amount of bits equal to half of the architecture long size */
> > > > #define RCU_GP_CTR_BIT (sizeof(long) << 2)
> > > 
> > > You lost me on this one:
> > > 
> > > 	sizeof(long) << 2 = 0x10
> > > 
> > > I could believe the following (run on a 32-bit machine):
> > > 
> > > 	1 << (sizeof(long) * 8 - 1) = 0x80000000
> > > 
> > > Or, if you were wanting to use a bit halfway up the word, perhaps this:
> > > 
> > > 	1 << (sizeof(long) * 4 - 1) = 0x8000
> > > 
> > > Or am I confused?
> > 
> > Well, I am at least partly confused.  You were wanting a low-order bit,
> > so you want to lose the "- 1" above.  Here are some of the possibilities:
> > 
> > 	sizeof(long) = 0x4
> > 	sizeof(long) << 2 = 0x10
> > 	1 << (sizeof(long) * 8 - 1) = 0x80000000
> > 	1 << (sizeof(long) * 4) = 0x10000
> > 	1 << (sizeof(long) * 4 - 1) = 0x8000
> > 	1 << (sizeof(long) * 2) = 0x100
> > 	1 << (sizeof(long) * 2 - 1) = 0x80
> > 
> > My guess is that 1 << (sizeof(long) * 4) and 1 << (sizeof(long) * 2)
> > are of the most interest.
> > 
> 
> Exactly. I'll change it to :
> 
> #define RCU_GP_CTR_BIT          (1 << (sizeof(long) << 2))
> 
> I somehow thought this define was used as a bit number rather than the
> bit mask.

Ah!  Been there, done that!  ;-)

							Thanx, Paul
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