Re: [take2] OOM documentation update [was: Linux killed Kenny, bastard!]

From: Evgeniy Polyakov
Date: Wed Jan 14 2009 - 17:10:56 EST


On Wed, Jan 14, 2009 at 04:53:16PM -0500, Bryan Donlan (bdonlan@xxxxxxxxx) wrote:
> On Wed, Jan 14, 2009 at 12:06 PM, Evgeniy Polyakov <zbr@xxxxxxxxxxx> wrote:
>
> > + * resulted score is multiplied by the two in the power of oom_adj when it is
> > + positive, and divided otherwise, i.e.
> > + points <<= oom_adj when it is positive and
> > + points >>= oom_adj otherwise
>
> Two to the power of a negative number is equivalent to dividing by two
> to the power of said exponent's absolute value, making this paragraph
> more than a bit confusing - indeed, a literal read would make it
> equivalent to multiplying by 2^abs(oom_adj).
>
> I would think that the following would be enough:
> * The resulting score is multiplied by two to the power of oom_adj.

Yes, I think it is enough with shift example.

Thanks guys I will update the doc.

--
Evgeniy Polyakov
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