Re: [PATCH 1/2] tracing/function-return-tracer: Make the function return tracer lockless

From: Frédéric Weisbecker
Date: Thu Nov 13 2008 - 12:27:01 EST


2008/11/13 Ingo Molnar <mingo@xxxxxxx>:
> "prev_global_time" also acts as a global serializer: it ensures that
> events are timestamped in a monotonic and ordered way.
>
> i.e. something like this (pseudocode, without the cmpxchg):
>
> u64 prev_global_time;
>
> DEFINE_PER_CPU(prev_local_time);
>
> u64 global_time()
> {
> u64 now, delta, now_global;
>
> prev_global = prev_global_time;
> now = sched_clock();
> delta = now - per_cpu(prev_local_time, this_cpu);
> per_cpu(prev_local_time, this_cpu) = now;
>
> now_global = prev_global + delta;
> prev_global = now_global;
>
> return now_global;
> }
>
> note how we build "global time" out of "local time".
>
> The cmpxchg would be used to put the above one into a loop, and
> instead of updating the global time in a racy way:
>
> prev_global = now_global;
>
> We'd update it via the cmpxchg:
>
> atomic64_t prev_global_time;
>
> ...
>
> while (atomic64_cmpxchg(&prev_global_time,
> prev_global, now_global) != prev_global) {
> [...]
> }
>
> To make sure the global time goes monotonic. (this way we also avoid a
> spinlock - locks are fragile for instrumentation)

Ok, I understand better.
But consider the following:

u64 global_time()
{
u64 now, delta, now_global;
prev_global = prev_global_time;

while (atomic64_cmpxchg(&prev_global_time,
prev_global, now_global) != prev_global) {

now = sched_clock();
delta = now - per_cpu(prev_local_time, this_cpu);
per_cpu(prev_local_time, this_cpu) = now;
now_global = prev_global + delta;
prev_global = now_global;
}
return now_global;
}

Sarting with prev_global_time = 0
If we have two cpu and the above function is executed 5 times on the first cpu.
We couldl have per_cpu(prev_local_time) = 50 for example. And so
prev_global_time will be equal to 50.

Just after that, almost at the same time, cpu2 calls global_time()

delta will be equal to 50 (sched_clock() - per_cpu(prev_local_time)
which is 0) and prev_global_time will be 50 + 50 = 100.
This is not consistent.
I don't know where but I'm pretty sure I missed something....
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