Re: C language lawyers needed

From: H. Peter Anvin
Date: Wed Aug 27 2008 - 18:00:28 EST


Roland Dreier wrote:

A fairly small test case that I don't understand either is:

unsigned foo(int x)
{
return (((x & 0xffffff) | (1 << 30)) & 0xff000000) >> 24;
}

just running "gcc -c" (ie no extra warnings enabled) on that produces
the same:

b.c: In function 'foo':
b.c:3: warning: integer overflow in expression

I'm sure there's some promotion rule or something that makes sense of
this, but it's a mystery to me...


Looks like a gcc bug to me.

0xff000000 is unsigned, like any hexadecimal constant.

unsigned foo(int x)
{
return ((x & 0xffffff) | (1 << 30)) & 0x80000000;
}

... is enough to reproduce the bug -- explicitly casting either side or both of the & operator to unsigned doesn't affect the warning, either.

-hpa
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