Re: Ordered Sorted List

From: Richard Knutsson
Date: Sat Nov 26 2005 - 07:11:02 EST


Nanakos Chrysostomos wrote:

Hi ,all.Can someone please explain this source code with an example???



Homework?

***********************************************************************
#include <stdio.h>

typedef struct list_tag {
int data;
struct list_tag *next;
}ListNode;

typedef ListNode *slist;
slist empty = NULL;

void slistInsert(slist *sp,int t)
{
ListNode *n=(ListNode *)malloc(sizeof(ListNode));
if(n == NULL)
{
printf("Out of memory\n");
exit(1);
}
n->data = t;
while(*sp!=NULL && (*sp)->data < t)
{
sp = &((*sp)->next); //Why we do this here,i miss this point
}


This is a _sorted_ list, right. So somehow we have to sort it.
What it does is to either find a node with a value higher then 't', or it reach the end of the list. Meanwhile, it just continue walking the list.

n->next = *sp;
*sp = n;


... so here we hock the rest of the list with the new node.

}


void slistRemove(slist *sp,int t)
{
ListNode *n;
while(*sp!=NULL && (*sp)->data <t)
sp = &((*sp)->next);
if(*sp == NULL)
{
printf("Not found\n");
exit(1);
}

n=*sp;
*sp = (*sp)->next;
free(n);
}

void slistPrint(slist s)
{
ListNode *n;
for(n=s;n!=NULL; n=n->next)
printf("%d\n",n->data);
}

void main()
{



NULL

slistInsert(&empty,4);


4->NULL

slistInsert(&empty,8);


4->8->NULL

slistInsert(&empty,24);

4->8->24->NULL

slistInsert(&empty,50);


4->8->24->50->NULL

slistInsert(&empty,20);


4->8->20->24->50->NULL

slistInsert(&empty,2);


2->4->8->20->24->50->NULL

slistRemove(&empty,4);


Remove first value equal or more than 4.
2->8->20->24->50->NULL

slistInsert(&empty,18);


2->8->18->20->24->50->NULL

slistPrint(empty);


2
8
18
20
24
50

}

Thank you very much in advance.


cu
/Richard Knutsson
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