Re: a 15 GB file on tmpfs

[Stefan Smietanowski]

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Bernd Petrovitsch wrote:
> On Wed, 2005-07-20 at 14:16 +0200, Bastiaan Naber wrote:
> [...]
> 
>>I have a 15 GB file which I want to place in memory via tmpfs. I want to do 
>>this because I need to have this data accessible with a very low seek time.
> 
> 
> Apart fromn the 32-vs-64bit thing: Isn't it enough (and simpler and more
> flexible) to mmap(2) that file and mlock(2) it afterwards?
> 
> 	Bernd

On 32bit arches, a pointer is 32bit large.
On 64bit arches, a pointer is 64bit large.

You can't mmap() the whole file if it's larger than 32bit on a 32bit
arch.

 void *mmap(void *start, size_t length, int prot, int flags,
       int fd, off_t offset);

test.c:
#include <sys/mman.h>
int main(void)
{
  printf("sizeof(void *): %d\n", sizeof(void *));
  printf("sizeof(size_t): %d\n", sizeof(size_t));
}

On a 64bit machine:
$ gcc test.c -o test64 ; ./test64; file ./test64
sizeof(void *): 8
sizeof(size_t): 8
test64: ELF 64-bit LSB executable, AMD x86-64, version 1 (SYSV), for
GNU/Linux 2.4.0, dynamically linked (uses shared libs), not stripped

On a 32bit machine (or in this case, 32bit userland on a 64bit machine):
$ gcc -m32 test.c -o test32 ; ./test32; file ./test32
sizeof(void *): 4
sizeof(size_t): 4
test32: ELF 32-bit LSB executable, Intel 80386, version 1 (SYSV), for
GNU/Linux 2.2.5, dynamically linked (uses shared libs), not stripped

Meaning both the pointer and the size argument are only 32bit (4byte)
on 32-bit arches and 64bit (8 byte) on 64bit arches.

// Stefan
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