AFAIK malloc will not return you memory more than the total virtual memory
(RAM+swap) in the system. So if you want more than 2GB allocations from
malloc, make sure you have at least 2GB virtual mem, keeping aside some
space for the kernel.
--tomar
On Mon, 28 Jul 2003, Tung-Han Hsieh wrote:
> Hello,
>
> I am developing applications which requires more than 2GB memory.
> But I found that in my Linux system the malloc() cannot allocate
> more than 2GB memory. Here is the details of my system:
>
> CPU: Pentium 4 2.53 GHz
> RAM: 2 GB
> Swap: 512 MB
> OS: Debian-3.0 stable
> Kernel: 2.4.20
> gcc: 2.95.4 20011002
> glibc: 2.2.5-6
>
> In theory, in a 32-bits machine the maximum allocatable memory
> is up to 4GB. But in the following very simple testing program:
>
> =====================================================================
> #include <stdio.h>
> #include <stdlib.h>
>
> main()
> {
> size_t l;
> char *s1=NULL, *s2=NULL;
>
> l = 1024*1024*1024;
>
> s1 = malloc(l);
> s2 = malloc(l);
> if (! s1) printf("s1 malloc failed\n");
> if (! s2) printf("s2 malloc failed\n");
> }
> =====================================================================
>
> only the block for s1 can be allocated. Further, if I change the
> program to
>
> =====================================================================
> #include <stdio.h>
> #include <stdlib.h>
>
> main()
> {
> size_t l;
> char *s1=NULL;
>
> l = 2*1024*1024*1024;
>
> s1 = malloc(l);
> if (! s1) printf("s1 malloc failed\n");
> }
> =====================================================================
>
> the gcc complier complain to me that "foo.c:9: warning: integer overflow
> in expression" during the compilation (I use: "gcc foo.c" to compile
> it),
> and the block for s1 cannot be allocated at all. I am wondering if there
> is any way to overcome the 2GB limit.
>
> Thank you very much for your reply in advance.
>
>
> Best Regards,
>
> T.H.Hsieh
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