Re: asm (lidt) question

From: Jamie Lokier (
Date: Tue Jul 22 2003 - 12:27:22 EST

Davide Libenzi wrote:
> IMHO, since "var" is really an output parameter.

"var" is read, not written.
I think you are confusing "lidt" with "sidt".


> __asm__ __volatile__("lidt %0": :"m" (var));

is the better choice, and that's why I wrote it in reboot.c :)

-- Jamie
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to
More majordomo info at
Please read the FAQ at

This archive was generated by hypermail 2b29 : Wed Jul 23 2003 - 22:00:47 EST