Ed Tomlinson wrote:
> Jamie Lokier wrote:
>
> > jtimeout = 0;
> > if (timeout) {
> > /* Careful about overflow in the intermediate values */
> > if ((unsigned long) timeout < MAX_SCHEDULE_TIMEOUT / HZ)
> > jtimeout = (unsigned long)(timeout*HZ+999)/1000+1;
> > else /* Negative or overflow */
> > jtimeout = MAX_SCHEDULE_TIMEOUT;
> > }
>
> Why assume HZ=1000? Would not:
>
> timeout = (unsigned long)(timeout*HZ+(HZ-1))/HZ+1;
>
> make more sense?
No, that's silly. Why do you want to multiply by HZ and then divide by HZ?
-- Jamie
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This archive was generated by hypermail 2b29 : Thu Jan 23 2003 - 22:00:29 EST