> void dump_stack(void)
> {
> - show_stack(0);
> + unsigned long stack;
> +
> + show_trace(&stack);
> }
Doesn't this mean that dump_stack no longer dumps the stack?
(seems somewhat counter-intuitive)
Can't code which only wants a trace just call show_trace instead?
M.
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This archive was generated by hypermail 2b29 : Mon Oct 07 2002 - 22:00:34 EST