Hello,
I have been investigating kernel behavior ( I am running 2.4.3) in out of
memory conditions with swap completely disabled and discovered a rather
interesting behavior. If you run the following code:
#include <stdio.h>
#include <stdlib.h>
#define LEAK_BLOCK (1024*1024)
#define MB (1024*1024)
int main()
{
unsigned long total = 0;
for (;;)
{
char* p, *p_end;
if(!(p=malloc(LEAK_BLOCK)))
{
fprintf(stderr, "malloc() failed\n");
exit(1);
}
p_end = p + LEAK_BLOCK;
while(p < p_end)
*p++ = 0;
total += LEAK_BLOCK;
printf("Allocated %d MB\n", total/MB);
}
return 0;
}
the process eventually gets killed by the kernel, rather than getting an
error from malloc() as you would logically expect
I have straced the process and see just a bunch of old_mmap() calls like this:
old_mmap(NULL, 1052672, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1,
0)
= 0x46b6a000
( in addition to writes to stdout, of course). So it looks like old_mmap()
never returns an error.
Can somebody explain this behavior? To me it looks like a bug...
--
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/ |/ /_ __/ __/ __ \/ / Sasha Pachev <sasha@mysql.com>
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This archive was generated by hypermail 2b29 : Sat Jul 07 2001 - 21:00:19 EST