On Thu, May 04, 2000 at 02:50:12AM -0700, George Anzinger wrote:
> I wrote:
>
> c = (c - d)>>n + d;
Are you sure you don't want c = (c - d >> n) + d;?
> and tested for values of 0 < c < 40, 1 < d < 40 and 0 < n < 80.
Are you sure what will happen if d is bigger then c? I have no idea if
that can be the case where you want to use it.
I have no idea what the standard says about shift with negative numbers,
but gcc always seems to do the same, wether it's signed or unsigned. -1 >>
32 still is -1. I assumed it would be 0 for unsigned, but I seem to be
wrong on this.
Kurt
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