> Well the problem is bad 'C' code. It's not the compiler's fault. It's
> just doing what it's told to do.
> char str="mystring";
> declares a string on the stack with room for 12 bytes. However it is
> initialized with only 9 (8 characters + the implied \0). So the rest
> of the area has to be zeroed, which the compiler does.
No it doesn't. For all C is required to care about, it could be stored as:
"mystring\0bla" The definition is 12 bytes on the stack, the first nine being
-- Ben Kosse <firstname.lastname@example.org>
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